Tuesday 10th Nov

Paper III: Objective – General Mathematics

10:00am – 11:45am

Paper II: Essay – General Mathematics

12:00noon – 2:30pm

===============

MATHS OBJ

1-10: ACBAECABAE

11-20: CCABBCAAEC

21-30: BBEBBBACBD

31-40: CCADBAEABD

41-50: DEBBBCCBBD

51-60: DACEADAEEA

loading...

No. 8 corrected

making some correction to No. 8

No. 8 added

interested in owning a site like exampoint.com.ng? chat me asap. If you don't have money don't chat me.

WAEC English Questions and Answers 2023. WAEC Eng Expo for Theory & Objective (OBJ) PDF: verified & correct expo Solved Solutions, 2023 NECO MATHEMATICS ANSWERS. 2023 WAEC EXAM English Questions and Answers

- How to get 2023 Mathematics WAEC QUESTION AND ANSWERS before the exam? To get 2023 NECO MATHEMATICS ANSWERS midnight before the exam, all you need to do is to visit gistpower.com with the pin sent to you by the admin and login. With the pin, you can have a full access to 2023 NECO MATHEMATICS ANSWERS
- When do I get Verified 2023 Mathematics WAEC QUESTION AND ANSWERS? You will get 2023 NECO MATHEMATICS ANSWERS a night to the exam because is an important subject.
- After using 2023 Mathematics WAEC ANSWERS, How many am I assured of in ? You will score between 7As - 9As in if you write verbatim 2023 NECO MATHEMATICS ANSWERS.
- How verified is your 2023 Mathematics WAEC ANSWERS? Our 2023 NECO MATHEMATICS ANSWERS is 100% verified and legit and it is worthy to be trusted because it from gistpower.com which is the most trusted website for exam runs in Nigeria.
- Where do I get 2023 Mathematics WAEC QUESTION AND ANSWERS? You can get 2023 NECO MATHEMATICS ANSWERS only from gistpower.com
- Is the answers on this page actually the main 2023 NECO MATHEMATICS ANSWERS? No, This is 2020 NECO MATHEMATICS ANSWERS, to get 2023 NECO MATHEMATICS ANSWERS, you need to subscribe with us by texting or WhatsApping us.
- How do I subscribe for 2023 Mathematics WAEC Questions & ANSWERS? To subscribe for 2023 Mathematics WAEC Questions & ANSWERS, Message 07058713598 starting that you need 2023 Mathematics WAEC Questions & ANSWERS a day to the exam.

**(1a)
x¹ y¹. x¹ y¹
A (6,5). B ( -2 ,7)
The equation of a straight line
y² - y¹/x² - x¹ = y-y/x¹-x¹
7-5/-2-6 = y-5/x-6
2/-8 = y-5/x-6
-1/4 = y-5/x-6
4(y-5)= -1(x-6)
4y-20= -x+6
4y+x=6+20
4y+x=26
(1b)
∫² (2x + 9)dx
-²
2x²/2+9x + c|²_¹
x² + 9x + c|²_¹
(2² + 9(2) + C) - ((-1)² + 9 (-1)+ c)
(4+18+c) - (1-9+C)
(22 + C) - (-8 + C)
22+C + 8 - C
=30.
===================**

**(2a)
To calculate u; 18+5+12+u=52
35+u=52
u=52-32=17
u=17
To calculate v
6+5+12+v=35
23+v=35
v=35-23=12
v=12
To calculate w
w+18+17+6+5+12+12
=100
w+70=100
w=100+70=30
w=30
(2b)
at least two means =18+6+5+12=41
; 41 tourist travelled by at least two means of transportation.
==============
(3a)
(i)median =6+6/2=12/2=6
(ii)median + range = 6+7=13
Range = highest value - lowest value = 10-3=7
(3b)
Pr(both pass)
=2/5*3/4=6/20=3/10.
=====================
(4a)
x²+3x-28=0
x²+7x-4x-28=0
x(x+7)-4(x+7)=0
(x-4)(x+7)=0
x-4=0 or x+7=0
x=0+4 or x=0-7
x=4 or -7
(4b)
8x/9 - 3x/2 =5/6 - x/1
L.c.m=54
6*8x-27*3x=9*5-54*x
48x-81x=45-54x
48x-81x+54x=45
21x/21=45/21
x=45/21=15/7=2⅐**

(5a)

d/dx(4x³ - 2x + 4)⁵

= 5(4x³-2x+4)⁴ × (12x² - 2)

= 10(6x² - 1)(4x³ - 2x + 4)⁴

(5b)

5/3(2-x) - (1-x)/(2-x) = 2/3

Multiply through with 3(2-x)

3(2-x)[5/3(2-x)] -3(2-x)[1-x/2-x] = 3(2-x)(2/3)

5 - 3(1-x) = (2 - x)(2)

5 - 3 + 3x = 4 - 2x

3x + 2x = 4 + 3 - 5

5x = 2

X = 2/5

=================

(6)

(6ai)

Volume of sphere = 9 ⅓ ×(its surface area)

4/3πr³ = 28/3×4πr²

r = 28 units

Surface area = 4πr²

= 4x22/7×28×28

= 9856 units squared.

(6aii)

Volume = 9 ⅓ × 9856

= 28/3 × 9856

= 91989.33

=91989 cubic units

(6b)

log10(3x - 5)² - log10(4x -3)² = log10 25

Log10(3x - 5/4x - 3)² = log10 25

(3x - 5/4x - 3)² = 25

Square root of both sides gives

3x-5/4x-3 = ±5

3x-5 = 5(4x-3) OR 3x-5 = 5(4x-3)

3x-5 = 20x-15 OR 3x-5 = 20x+15

3x-20x = 5-15 OR 3x+20x = 15+5

-17x = -10 OR 23x = 20

X = 10/17 OR x = 20/23

================

(7)

(7a)

Given: 3x + 5y = 10

5y = -3x + 10 OR y = -3/5x+ 2

Gradient of the straight line = -1 ÷ (-2/5)

= 5/3

Equation of line:y-2/x-3 = 5/3

3y-6 = 5x - 15

3y = 5x - 15 + 6

3y = 5x - 9

y = 5/3x - 3

Intercept of line = -3

(7b)

Amount = P(1+R/100)³

=8000(1+5/100)³

=8000(1.05)³ OR 8000(1.05/100)³

=8000×1.157625

=#9261

Compound interest = Amount - principal

= 9261 - 8000

= ₦1,261

(8a)

Ta; a+8d=50 --------(1)

T12; a+11d=65---------(2)

Subtract equation (1) from (2)

a+11d-(a+8d)=65-50

a+11d-a-8d=15

11d-8d=15

3d/3=15/3

d=5

Substitute for d=5 in each equation (1)

a+8d=50

a+8(5)=50

a+40=50

a=50-40=10

Sn=n/2(2a+(n-1)d)

S70=70/2(2*10+(70-1)5)

=35(20+69*5)

=35*365=12,775

===========

(10a)

Let the woman's age be W

Let the daughter's age be d

Given: w = 4d-----(1)

Given:(w+5)²=(d+5)²+120--(2)

Put eqn(1)into(2)

(4d+5)² = (d+5)² + 120

(4d+5)² - (d+5)² = 120

[4d+5+d+5][4d+5-d-5] = 120

[5d+10][3d] = 120

5(d+2)(3d) = 120

15(d+2)(d) = 120

d(d+2) = 8

d² + 2d - 8 = 0

d² + 4d - 2d - 8 = 0

d(d+4) -2(d+4) = 0

(d - 2)(d + 4) = 0

d - 2 = 0 (only)

d = 2

Daughter is 2 years old

(10b)

t = w + wy²/PZ

Multiply through by PZ

Pat = PWZ + wy²

Wy² = ptz - pwz

y² = Pz(t - w)/w

y = ±√PZ(t - w)/w

If P = 5, Z = 10, t = 9, w=3

y = ±√(5)(10) (9-3)/3

y = ±√(5)(10)(6)/3

y = ±√100

y = ±10

==================

(11)

(11)

|Score|5-9|10-14|15-19|20-24|25-29|30-34|

|Frequency|3|10-T|3T|8|2T+2|T+2|

(a)Ʃ+=50

3+10-T+3T+8+2T+2+T+2=50

3+10+8+2+2-T+3T+2T+T=50

25+5T=50

5T=50-20

5T/5=25/5

T=5

(11b)

|Score|5-9|10-14|15-19|20-24|25-29|30-34|

|Frequency|3|5|15|8|12|7|

The frequency of the modal class is 15.

(11c)

Tabulate.

|Score|5-9|10-14|15-19|20-24|25-29|30-34|

|F|3|5|1|5|8|1|2|7|50

|X|7|12|17|22|27|32|

|FX|21|60|255|176|324|224|1060

|X-x̅|-14.2|-9.2|-4.2|0.8|5.8|10.8|

|(X-x̅)²|201.64|84.64|17.64|0.64|33.64|116.64|

F|(X-x̅)|604.92|423.2|264.6|5.12|403.68|816.48|2518

Mean (x̅) =Ʃfx/Ʃf=1060/50=21.2

Variance =Ʃf(x-x̅)²/Ʃf

=2518/50

=50.36

**(12a)
y=²-2x-3
Tabulate
|x|-2|-1|0|1|2|3|
|y|5|0|-3|-4|-3|0|
(12b)
Graph.
(12c)
y=1-3x
|y|-2|-1|0|1|2|3|
|x|7|4|1|-2|-5|-8|
(12d)
(i)the root of the equation x² - 2x - 3= 1-3x are -3 and 1.6
(ii) the minimum value of y is - 4 and the corresponding value of x is 1**

loading...

WAEC English Questions and Answers 2023. WAEC Eng Expo for Theory & Objective (OBJ) PDF: verified & correct expo Solved Solutions, 2023 NECO MATHEMATICS ANSWERS. 2023 WAEC EXAM English Questions and Answers

Beware of Scammers.... Please always use 07058713598 for all your transactions to avoid being scammed.

NOTE: Any answer that does not have badge can be chnaged, removed or updated anytime. The badge means that the answers have been verified 100% (if used exactly, you're to get nothing but A1) while without the badge means that the answer is still under verification. If you're not in a hurry, please wait for answer to be verified before you copy.

Click on the drop down links to view answer under them.

Good Luck... Invite family and friends to gistpower.com... We are the best and we post, others copy from us.

2023 Waec Gce Health Science & Health Education answers free

2023 WAEC MATHEMATICS ANSWERS (MAY/JUNE)

2023 WAEC MAY/JUNE Chemistry Practical Answers

WAEC 2023 MAY/JUNE ECONOMICS ANSWERS

2023 WAEC MAY/JUNE AGRICULTURAL Sc. ANSWERS

2023 WAEC MAY/JUNE PHYSICS PRACTICAL

2023 WAEC MAY/JUNE HISTORY ANSWERS

2023 WAEC MAY/JUNE LIT. IN ENG. ANSWERS

2023 HOME MANAGEMENT WAEC ANSWERS